Word count for corrections 论题张贴者: boostrer
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boostrer 
美国
Local time: 04:16
正式会员 (自2007)
English英语译成Russian俄语
+ ...
I have a DOC file with tracked changes.
How can I count the inserted words using CAT tools (WF Pro, Trados, MemoQ)? Maybe, there are other methods?
Thank you
[Edited at 2012-03-29 23:35 GMT]
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Practicount can count them. Go to Settings/Applications, select Revisions in the middle column, then select „Count inserted text only”.
I had the same problem last week and worked like this (of course, try this on a copy):
Opened the tracked doc in Word, recorded the word count (C1), then saved the doc as „Webpage”.
Opened the Webpage in Notepad++ and performed the following replacements:
„msoIns” was replaced with „msoDel”
„&l... See more Practicount can count them. Go to Settings/Applications, select Revisions in the middle column, then select „Count inserted text only”.
I had the same problem last week and worked like this (of course, try this on a copy):
Opened the tracked doc in Word, recorded the word count (C1), then saved the doc as „Webpage”.
Opened the Webpage in Notepad++ and performed the following replacements:
„msoIns” was replaced with „msoDel”
„<ins” was replaced with „<del”
„</ins>” was replaced with „</del>”
in this order (ignore the quotation marks), then saved as "Hyper Text Markup Language File”.
Opened this file in Word and counted words (C2).
As in Notepad++ you transformed all inserted texts to deleted texts, the difference C1-C2 gives the number of the new (inserted) words. ▲ Collapse
| | | | | This may help too | Mar 30, 2012 |
Not sure if you want to count them specifically in CAT Tools, but there's another way to count them in Word, using the following macro (found it online):
Sub GetTCStats()
Dim lInsertsWords As Long
Dim lInsertsChar As Long
Dim lDeletesWords As Long
Dim lDeletesChar As Long
Dim sTemp As String
Dim oRevision As Revision
lInsertsWords = 0
lInsertsChar = 0
lDeletesWords = 0
lDel... See more Not sure if you want to count them specifically in CAT Tools, but there's another way to count them in Word, using the following macro (found it online):
Sub GetTCStats()
Dim lInsertsWords As Long
Dim lInsertsChar As Long
Dim lDeletesWords As Long
Dim lDeletesChar As Long
Dim sTemp As String
Dim oRevision As Revision
lInsertsWords = 0
lInsertsChar = 0
lDeletesWords = 0
lDeletesChar = 0
For Each oRevision In ActiveDocument.Revisions
Select Case oRevision.Type
Case wdRevisionInsert
lInsertsChar = lInsertsChar + Len(oRevision.Range.Text)
lInsertsWords = lInsertsWords + oRevision.Range.Words.Count
Case wdRevisionDelete
lDeletesChar = lDeletesChar + Len(oRevision.Range.Text)
lDeletesWords = lDeletesWords + oRevision.Range.Words.Count
End Select
Next oRevision
sTemp = "Insertions" & vbCrLf
sTemp = sTemp & " Words: " & lInsertsWords & vbCrLf
sTemp = sTemp & " Characters: " & lInsertsChar & vbCrLf
sTemp = sTemp & "Deletions" & vbCrLf
sTemp = sTemp & " Words: " & lDeletesWords & vbCrLf
sTemp = sTemp & " Characters: " & lDeletesChar & vbCrLf
MsgBox sTemp
End Sub
It works in Office 2010. However, I get the impression it is not accurate (in my case, it seemed to show more insertions). It can give you a rough estimate, though.
HTH ▲ Collapse
| | | | | Counting means hoping | Mar 30, 2012 |
Annamaria Amik wrote:
Not sure if you want to count them specifically in CAT Tools, but there's another way to count them in Word, using the following macro (found it online):
(...)
I get the impression it is not accurate (in my case, it seemed to show more insertions).
If insertions and deletions overlap each other or aren't separated clearly, the results may be unexpected. Try to insert three words and delete the middle one later on ...
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boostrer
美国
Local time: 04:16
正式会员 (自2007)
English英语译成Russian俄语
+ ...
主题发起人 | Thnak you all for your advice | Apr 2, 2012 |
My special thanks to István Hirsch. Practicount was the easiest way to solve the problem.
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